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4r^2-17r+4=0
a = 4; b = -17; c = +4;
Δ = b2-4ac
Δ = -172-4·4·4
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-15}{2*4}=\frac{2}{8} =1/4 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+15}{2*4}=\frac{32}{8} =4 $
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